2j^2+5j-7=0

Solution for 2j^2+5j-7=0 equation:

Simplifying
2j2 + 5j + -7 = 0

Reorder the terms:
-7 + 5j + 2j2 = 0

Solving
-7 + 5j + 2j2 = 0

Solving for variable 'j'.

Factor a trinomial.
(-7 + -2j)(1 + -1j) = 0

Subproblem 1
Set the factor '(-7 + -2j)' equal to zero and attempt to solve:

Simplifying
-7 + -2j = 0

Solving
-7 + -2j = 0

Move all terms containing j to the left, all other terms to the right.

Add '7' to each side of the equation.
-7 + 7 + -2j = 0 + 7

Combine like terms: -7 + 7 = 0
0 + -2j = 0 + 7
-2j = 0 + 7

Combine like terms: 0 + 7 = 7
-2j = 7

Divide each side by '-2'.
j = -3.5

Simplifying
j = -3.5
Subproblem 2
Set the factor '(1 + -1j)' equal to zero and attempt to solve:

Simplifying
1 + -1j = 0

Solving
1 + -1j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1j = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1j = 0 + -1
-1j = 0 + -1

Combine like terms: 0 + -1 = -1
-1j = -1

Divide each side by '-1'.
j = 1

Simplifying
j = 1
Solution
j = {-3.5, 1}